“A particle has an initial velocity of 100 m/s up to the right at 30° with the horizontal. The components of the acceleration are constant at ax=-4m/s^2 and ay=-20m/s^2. Computing the horizontal distance covered until the particle reaches a point 60m below its original elevation would be” In this problem, the given is ay = -20ft/s^2ay=-20m/s^2Sy=voyt+1/2ayt^2-60=50t-1/2(20) t^2t = 6s why did he substitute positive 20 instead of negative 20?

Estrella Luna , 3 Years ago

Grade 12th pass